GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure shown, J, K, and L are the centers of the thre
[#permalink]
29 Jul 2020, 10:39
29 Jul 2020, 10:39
Expert Reply
00:00
Question Stats:
80% (03:04) correct
19% (02:02) wrong based on 42 sessions
Hide Show timer Statistics
Attachment:
GRE In the figure shown, J, K, and L are the centers of the thre.jpg [ 32.38 KiB | Viewed 1987 times ]
In the figure shown, J, K, and L are the centers of the three circles. The radius of the circle with center J is four times the radius of the circle with center L, and the radius of the circle with center J is two times the radius of the circle with center K. If the sum of the areas of the three circles is \(525\pi\) square units, what is the measure, in units, of JL?
A. 35
B. 45
C. 50
D. 65
E. 70
Kudos for the right answer and explanation
Re: In the figure shown, J, K, and L are the centers of the thre
[#permalink]
29 Jul 2020, 10:45
29 Jul 2020, 10:45
1
Let the radius of the circle with center L be x.
=> the radius of the circle with center K = 2x
and, the radius of the circle with center J = 4x
Now, the sum of the areas of the three circles is 525π
=> π*x*x + π*(2x)*(2x) + π*(4x)*(4x) = 525*π
=> x^2 + 4*x^2 + 16*x^2 = 525
=> 21*x^2 = 525
=> x^2 = 21
=> x = 5
=> JL = 5 + 10 + 10 + 20 = 45
So, the answer is B.
=> the radius of the circle with center K = 2x
and, the radius of the circle with center J = 4x
Now, the sum of the areas of the three circles is 525π
=> π*x*x + π*(2x)*(2x) + π*(4x)*(4x) = 525*π
=> x^2 + 4*x^2 + 16*x^2 = 525
=> 21*x^2 = 525
=> x^2 = 21
=> x = 5
=> JL = 5 + 10 + 10 + 20 = 45
So, the answer is B.
Re: In the figure shown, J, K, and L are the centers of the thre
[#permalink]
22 Jun 2024, 13:00
22 Jun 2024, 13:00
JL = 5 + 10 + 10 + 20 = 45 please let me know how this value are selected.
