GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Liquid A is 32 percent iodine and the rest water. Liquid B i
[#permalink]
31 Jul 2020, 10:20
31 Jul 2020, 10:20
1
Expert Reply
21
Bookmarks
00:00
Question Stats:
58% (01:58) correct
41% (02:12) wrong based on 159 sessions
Hide Show timer Statistics
Liquid A is 32 percent iodine and the rest water. Liquid B is 17 percent iodine and the rest water.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The percentage of a 23 percent iodine mixture of liquid A and liquid B that is liquid A |
38 % |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: Liquid A is 32 percent iodine and the rest water. Liquid B i
[#permalink]
02 Aug 2020, 17:11
02 Aug 2020, 17:11
5
Expert Reply
1
Bookmarks
A=TBhis is a nice question.
Basically QA is asking you: what percent of the combined mixture which is 23% iodine overall is A.
In other words, of the new mixture what % is made by the iodine labeled as A
This question could be solved quickly using weighted average
\(32A+17B=23(A+B)\)
After manipulation we do have
\(9A=6B\)
This means that the ration \(\frac{B}{A}=\frac{3}{2}\) or \(\frac{A}{B}=\frac{2}{3}\)
So in the solution A represents 2 parts and B 3 parts AND overall all parts add up to 5
So the ratio \(\frac{A}{Overall} = \frac{2}{5} = 40\)%
So quantity A is 40% and B is 38%
\(A > B\)
The answer to this question is A
Basically QA is asking you: what percent of the combined mixture which is 23% iodine overall is A.
In other words, of the new mixture what % is made by the iodine labeled as A
This question could be solved quickly using weighted average
\(32A+17B=23(A+B)\)
After manipulation we do have
\(9A=6B\)
This means that the ration \(\frac{B}{A}=\frac{3}{2}\) or \(\frac{A}{B}=\frac{2}{3}\)
So in the solution A represents 2 parts and B 3 parts AND overall all parts add up to 5
So the ratio \(\frac{A}{Overall} = \frac{2}{5} = 40\)%
So quantity A is 40% and B is 38%
\(A > B\)
The answer to this question is A
General Discussion
Re: Liquid A is 32 percent iodine and the rest water. Liquid B i
[#permalink]
31 Jul 2020, 10:20
31 Jul 2020, 10:20
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
