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c=-c+1/c
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28 Jul 2020, 10:49
28 Jul 2020, 10:49
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Question Stats:
80% (00:40) correct
19% (00:56) wrong based on 67 sessions
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\(\bigcirc c=-c+\frac{1}{c}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The value of \(\bigcirc\) \(c\) if \(c=4\) |
The value of \(\bigcirc\) \(c\) if \(c=3\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: c=-c+1/c
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28 Jul 2020, 11:54
28 Jul 2020, 11:54
1
Carcass wrote:
\(\bigcirc c=-c+\frac{1}{c}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The value of \(\bigcirc\) \(c\) if \(c=4\) |
The value of \(\bigcirc\) \(c\) if \(c=3\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
If \(c=4\), then \(\bigcirc c=-c+\frac{1}{c}=-4+\frac{1}{-4}==-4-\frac{1}{4}=-4\frac{1}{4}\)
If \(c=3\), then \(\bigcirc c=-c+\frac{1}{c}=-3+\frac{1}{-3}==-3-\frac{1}{3}=-3\frac{1}{3}\)
\(-3\frac{1}{3} > -4\frac{1}{4}\)
Answer: B
Re: c=-c+1/c
[#permalink]
02 Aug 2020, 01:44
02 Aug 2020, 01:44
1
Quantity A:
-4+(1/4)
Quantity B:
-3+(1/3)
-3>-4 and (1/3)>(1/4)
so -3+(1/3)>-4+(1/4)
Quantity B> Quantity A
Final answer: B
-4+(1/4)
Quantity B:
-3+(1/3)
-3>-4 and (1/3)>(1/4)
so -3+(1/3)>-4+(1/4)
Quantity B> Quantity A
Final answer: B
