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x < y < 1 and c > d QUANTITY A
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23 Feb 2020, 06:15
23 Feb 2020, 06:15
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43% (01:14) wrong based on 79 sessions
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\(x < y < 1\) and \(c > d\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(x^{-(c-d)}\) |
\(y^{(d-c)}\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
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x < y < 1 and c > d QUANTITY A
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23 Feb 2020, 09:19
23 Feb 2020, 09:19
1
Asif123 wrote:
\(x < y < 1\) and \(c > d\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(x^{-(c-d)}\) |
\(y^{(d-c)}\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
First recognize that \(-(c-d) = -c+d = d-c\)
So, we have:
QUANTITY A: \(x^{d-c}\)
QUANTITY B: \(y^{d-c}\)
Since I'm not too sure where to go from here, I'll test some possible values.
case i: Since \(x < y < 1\) and \(c > d\) one possible set of values is x = -2, y = -1, c = 2 and d = 1
We get:
QUANTITY A: \(x^{d-c}=(-2)^{1-2}=(-2)^{-1}=\frac{1}{-2}=-\frac{1}{2}\)
QUANTITY B: \(y^{d-c}=(-1)^{1-2}=(-1)^{-1}=\frac{1}{-1}=-1\)
In this case, Quantity A is greater
case ii: Since \(x < y < 1\) and \(c > d\) one possible set of values is x = -2, y = 0.5, c = 2 and d = 1
We get:
QUANTITY A: \(x^{d-c}=(-2)^{1-2}=(-2)^{-1}=\frac{1}{-2}=-\frac{1}{2}\)
QUANTITY B: \(y^{d-c}=(0.5)^{1-2}=(0.5)^{-1}=\frac{1}{(0.5)}=2\)
In this case, Quantity B is greater
Answer: D
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Re: x < y < 1 and c > d QUANTITY A
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23 Feb 2020, 11:01
23 Feb 2020, 11:01
1
Expert Reply
\(x < y < 1\) and \(c > d\)
x and y are less than 1 . However, they could be negative integers or positive fractions less than 1. We do not know
To c and d we could apply the same reasoning for x and y. We do not know.
Straight D without further ado.
Regards
x and y are less than 1 . However, they could be negative integers or positive fractions less than 1. We do not know
To c and d we could apply the same reasoning for x and y. We do not know.
Straight D without further ado.
Regards
