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The average (arithmetic mean) of a, b, c, and d is 12. The a
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05 Aug 2020, 11:31
05 Aug 2020, 11:31
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The average (arithmetic mean) of a, b, c, and d is 12. The average of b, c, d, and e is 17. What is the value of 3( e − a) ?
A. \(\frac{ 240}{7}\)
B. 48
C. 54
D. 58
E. 60
A. \(\frac{ 240}{7}\)
B. 48
C. 54
D. 58
E. 60
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Re: The average (arithmetic mean) of a, b, c, and d is 12. The a
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06 Aug 2020, 13:34
06 Aug 2020, 13:34
1
Carcass wrote:
The average (arithmetic mean) of a, b, c, and d is 12. The average of b, c, d, and e is 17. What is the value of 3( e − a) ?
A. \(\frac{ 240}{7}\)
B. 48
C. 54
D. 58
E. 60
A. \(\frac{ 240}{7}\)
B. 48
C. 54
D. 58
E. 60
Given: The average (arithmetic mean) of a, b, c, and d is 12
We can write: (a + b + c + d)/4 = 12
Multiply both sides of the equation by 4 to get: a + b + c + d = 48
Given: The average of b, c, d, and e is 17
We can write: (b + c + d + e)/4 = 17
Multiply both sides of the equation by 4 to get: b + c + d + e = 68
So we have:
b + c + d + e = 68
a + b + c + d = 48
Subtract the bottom equation from the top equation to get: (b + c + d + e) - (a + b + c + d) = 68 - 48
Simplify: e - a = 20
Multiply both sides of the equation by 3 to get: 3(e - a) = 60
Answer: E
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Re: The average (arithmetic mean) of a, b, c, and d is 12. The a [#permalink]
06 Aug 2020, 13:34
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