GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
QOTD#26 Which of the following is the best approximation of
[#permalink]
Updated on: 19 Feb 2020, 10:09
Updated on: 19 Feb 2020, 10:09
Expert Reply
3
Bookmarks
00:00
Question Stats:
89% (01:01) correct
10% (00:57) wrong based on 47 sessions
Hide Show timer Statistics
Which of the following is the best approximation of \(\sqrt{98.763 \times \frac{0.49^2}{0.252}}\)?
A. \(\frac{1}{4}\)
B. \(\frac{1}{2}\)
C. \(5\)
D. \(10\)
E. \(25\)
A. \(\frac{1}{4}\)
B. \(\frac{1}{2}\)
C. \(5\)
D. \(10\)
E. \(25\)
Drill 1
Question: 12
Page: 284
Question: 12
Page: 284
Re: QOTD#26 Which of the following is the best approximation of
[#permalink]
13 Oct 2016, 13:31
13 Oct 2016, 13:31
Expert Reply
Explanation
Try rounding your values before you calculate. The expression can be estimated as:
\(\sqrt{100*0.5^2/0.25}\)=\(\sqrt{100*0.25/0.25}\)=\(\sqrt{100}\)=\(10\).
Hence option D is correct.
Try rounding your values before you calculate. The expression can be estimated as:
\(\sqrt{100*0.5^2/0.25}\)=\(\sqrt{100*0.25/0.25}\)=\(\sqrt{100}\)=\(10\).
Hence option D is correct.
Re: QOTD#26 Which of the following is the best approximation of
[#permalink]
19 Feb 2020, 10:10
19 Feb 2020, 10:10
Expert Reply
Bump further discussion
