I agree with the answer but you must be careful because that is NOT the only case. It doesn't say who has triple the other. Y with 24 could have triple someone with 8, and the remainder would be 68. Or either C or A could have triple of Y, which is 72, and the remainder would be 4. So there are three possible distributions: 1) 19-24-57; 2) 8-24-68; and 3) 4-24-72. Note that 24 is always the middle value.

The number of chocolates Albert has if Clarice has more chocolates than Yolanta:
1) Clarice has 57, Albert has 19.
2) Clarice has 68, Albert has 8.
3) Clarice has 72, Albert has 4.


The number of chocolates Clarice has if Yolanta has more chocolates than Albert:
1) Albert has 19, Clarice has 57.
2) Albert has 8, Clarice has 68.
3) Albert has 4, Clarice has 72.

Here it is clear that choice A always picks the lowest amount, since Yolanta will always have the middle value and Clarice has even more. Choice B always picks the highest amount, since, again, Yolanta will have the middle value and Albert will have less. That only leaves the highest value. Although it works here for any of the possible distributions, a different question may not work so well.