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In a class with 20 students, a test was administered and was
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29 Jul 2018, 04:29
29 Jul 2018, 04:29
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43% (14:28) correct
56% (01:43) wrong based on 195 sessions
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In a class with 20 students, a test was administered and was scored only in whole numbers from 0 to 10. At least one student got every possible score, and the average score was 7.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The lowest score that could have been received by more than one student |
\(4\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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In a class with 20 students, a test was administered and was
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06 Apr 2020, 15:32
06 Apr 2020, 15:32
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sandy wrote:
In a class with 20 students, a test was administered and was scored only in whole numbers from 0 to 10. At least one student got every possible score, and the average score was 7.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The lowest score that could have been received by more than one student |
\(4\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
In a class with 20 students, the average score was 7.
We can write: (sum of all 20 scores)/20 = 7
Multiply both sides of the equation by 20 to get: sum of all 20 scores = 140
At least one student got every possible score
Since every score from 0 to 10 has been achieved, the first 11 score in the class are as follows:
{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ?, ?, ?, ?, ?, ?, ?, ?, ?}
QUANTITY A: The lowest score that could have been received by more than one student
So far, the sum of the first 11 scores = 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
140 - 55 = 85, which means the remaining (missing) 9 scores must add to 85
Our goal is to MINIMIZE one of the 9 remaining scores (keeping in mind that the SUM of those 9 scores must be 85)
To MINIMIZE one of the remaining 9 scores, we'll MAXIMIZE the other eight scores.
Since the maximum possible test score is 10, let's let eight of the remaining scores be 10.
Since the some of those eight 10's is 80, and since the SUM of the remaining 9 scores must be 85, the last value must be 5
In other words, the test scores are: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10, 5}
So, 5 is The lowest score that could have been received by more than one student
We have:
QUANTITY A: 5
QUANTITY B: 4
Answer: A
Cheers,
Brent
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Re: In a class with 20 students, a test was administered and was
[#permalink]
03 Aug 2018, 00:20
03 Aug 2018, 00:20
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Since the avg of the class is 7, the total score of the class is 7*20 = 140
If there is a score of at least 0-10 inclusive we know that 9 people will score 85.
This is because 0+1+....10 = 55
Remaining is 140-55 = 85
85 has to be distributed between 9 remaining students.
Only when 1 of them gets 5 remaining 8 will get 80/8 =10 each. 10 is the maximum possible hence 5 is the least that two person can get.
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Posted from my mobile device
If there is a score of at least 0-10 inclusive we know that 9 people will score 85.
This is because 0+1+....10 = 55
Remaining is 140-55 = 85
85 has to be distributed between 9 remaining students.
Only when 1 of them gets 5 remaining 8 will get 80/8 =10 each. 10 is the maximum possible hence 5 is the least that two person can get.
Posted from my mobile device
Posted from my mobile device
