Carcass wrote:
A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)
A committee is composed of w women and m men. If 3 women and 2 men are added to the committee . . . After the 3 women and 2 men are added, we have...
w+3 women and
m+2 men
. . . and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented byP(select woman) = (# of women in committee)/(TOTAL # of people on committee)
= (
w+3)/(
w+3 +
m+2 )
= (w+3)/(w+m+5)
Answer: E
Cheers,
Brent