Carcass wrote:
There is a total of 120 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/4 and the probability that it will be green is 1/3. What is the probability that the marble will be either red or blue ?
(A) 1/6
(B) 1/4
(C) 2/7
(D) 1/3
(E) 5/12
...the probability that it [the marble] will be white is 1/4So, 1/4 of the 120 marbles are white.
In other words, there are
30 white marbles.
...the probability that it [the marble] will be green is 1/3So, 1/3 of the 120 marbles are green .
In other words, there are
40 green marbles.
Altogether, there are
70 marbles that are EITHER white or green.
This means that the
remaining 50 marbles are EITHER red or blue.
So, P(selected marble is EITHER red or blue) =
50/120
= 5/12
Answer: E
Cheers,
Brent