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A triangle has a base of length b, an altitude correspo
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27 Aug 2020, 10:26
27 Aug 2020, 10:26
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A triangle has a base of length b, an altitude corresponding to that base of length h, and h=3b. Which of the following expresses the area of the triangle, in terms of b?
A. \(\frac{1}{6} b^2\)
B. \(\frac{3}{4} b^2\)
C. \(b^2\)
D. \(\frac{3}{2} b^2\)
E. \(6b^2\)
A. \(\frac{1}{6} b^2\)
B. \(\frac{3}{4} b^2\)
C. \(b^2\)
D. \(\frac{3}{2} b^2\)
E. \(6b^2\)
Re: A triangle has a base of length b, an altitude correspo
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27 Aug 2020, 10:26
27 Aug 2020, 10:26
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
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Re: A triangle has a base of length b, an altitude correspo
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28 Aug 2020, 07:14
28 Aug 2020, 07:14
1
Carcass wrote:
A triangle has a base of length b, an altitude corresponding to that base of length h, and h=3b. Which of the following expresses the area of the triangle, in terms of b?
A. \(\frac{1}{6} b^2\)
B. \(\frac{3}{4} b^2\)
C. \(b^2\)
D. \(\frac{3}{2} b^2\)
E. \(6b^2\)
A. \(\frac{1}{6} b^2\)
B. \(\frac{3}{4} b^2\)
C. \(b^2\)
D. \(\frac{3}{2} b^2\)
E. \(6b^2\)
Remind that an area of a triangle with a base \(b\) and a height \(h\) is \(\frac{1}{2}bh\).
Since we have \(h = 3b\), the area of the given triangle is
\(\frac{1}{2} bh = \frac{1}{2} b \cdot 3b = \frac{3}{2} b^2\).
Therefore, D is the right answer.
