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Re: The figure above shows a normal distribution with mean ? an [#permalink]
1
The mean is 45 minutes and the SD is 3 minutes.

42 minutes would be One Standard Deviation to the left of the mean.

Thus percentage of Tina's travel times to work greater than 42 minutes would be 34% + 50% = 84%

The Choice A is the right answer.
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Re: The figure above shows a normal distribution with mean ? an [#permalink]
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