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If the area of the above triangle is
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01 Sep 2020, 03:36
01 Sep 2020, 03:36
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76% (01:40) correct
23% (01:31) wrong based on 21 sessions
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GRE If the area of the above triangle is.png [ 9.5 KiB | Viewed 1219 times ]
If the area of the above triangle is \(8 \sqrt{3}\) what is the length of side \(AB\) ?
A. 3
B. 4
C. \(4 \sqrt{3}\)
D. \(6 \sqrt{3}\)
E. \(8 \sqrt{3}\)
KUDOS for the right solution and explanation
Re: If the area of the above triangle is
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01 Sep 2020, 21:39
01 Sep 2020, 21:39
As this is 30-60-90 triangle, so we can take side as x: √3 x: 2x.
If we use these lengths, we can get the length of any side
If we use these lengths, we can get the length of any side
Re: If the area of the above triangle is
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01 Sep 2020, 23:05
01 Sep 2020, 23:05
1
Area of Triangle = \(\frac{1}{2}\) L * W
Given area: 8\(\sqrt{3}\)
We know that,
30:60:90 triangle = L:W:H
x:x\(\sqrt{3}\): 2x
Area of Triangle = \(\frac{1}{2}\) L * W
8\(\sqrt{3}\) = \(\frac{1}{2 }\)* x * x\(\sqrt{3}\)
\(x^2\) = 16
x = 4 option B
Given area: 8\(\sqrt{3}\)
We know that,
30:60:90 triangle = L:W:H
x:x\(\sqrt{3}\): 2x
Area of Triangle = \(\frac{1}{2}\) L * W
8\(\sqrt{3}\) = \(\frac{1}{2 }\)* x * x\(\sqrt{3}\)
\(x^2\) = 16
x = 4 option B
