Last visit was: 23 Nov 2024, 00:42 It is currently 23 Nov 2024, 00:42

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
User avatar
Retired Moderator
Joined: 07 Jun 2014
Posts: 4813
Own Kudos [?]: 11194 [1]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
avatar
Manager
Manager
Joined: 08 Dec 2018
Posts: 94
Own Kudos [?]: 70 [0]
Given Kudos: 0
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30004
Own Kudos [?]: 36356 [0]
Given Kudos: 25927
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12196 [0]
Given Kudos: 136
Send PM
Re: GRE Math Challenge #48-39 points are placed inside [#permalink]
1
Yuck!
Ambiguous and grammatically flawed!
Skip this question.

Cheers,
Brent
Manager
Manager
Joined: 05 Aug 2020
Posts: 101
Own Kudos [?]: 244 [0]
Given Kudos: 14
Send PM
Re: GRE Math Challenge #48-39 points are placed inside [#permalink]
sandy wrote:
39 points are placed inside or on the surface of a perfect sphere.If 60% or less touch the surface, what is the maximum number of segments which, if connected from those points to form chords, could be diameter of the sphere?

A. 7
B. 11
C. 13
D. 23
E. 38


Here's how I solved it:

There are 39 points that are inside the sphere. Of those 39 points, 60% or less touch the surface. In other words, the percentage of points that touch the surface are between 0% and 60%, with the result being an integer.

60% of 39 is 23.4, so there has to exist a percentage slightly less than 60% that yields a total of 23 points on the surface of the sphere (it's about 58.97% of 39).

Since 23 is maximum number of points on the surface (given the parameters), to make the diameter, we would need pairs of points.

Therefore, we could make a maximum of 11 diameters, with one point without a pair, giving the answer B.
Prep Club for GRE Bot
Re: GRE Math Challenge #48-39 points are placed inside [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne