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Carol purchased one basket of fruit consisting of 4 Apples a
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03 Sep 2020, 10:28
03 Sep 2020, 10:28
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62% (01:44) correct
37% (02:49) wrong based on 43 sessions
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Carol purchased one basket of fruit consisting of 4 Apples and 2 Oranges and another basket of fruit consisting of 3 Apples and 5 Oranges. Carol is to select one piece of fruit at random from each of the two baskets. What is the probability that one of the two pieces of fruit selected will be an apple and the other will be an orange?
(A) 1/4
(B) 1/2
(C) 1/24
(D) 5/24
(E) 13/24
(A) 1/4
(B) 1/2
(C) 1/24
(D) 5/24
(E) 13/24
Re: Carol purchased one basket of fruit consisting of 4 Apples a
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03 Sep 2020, 10:29
03 Sep 2020, 10:29
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
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Joined: 10 Apr 2015
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Re: Carol purchased one basket of fruit consisting of 4 Apples a
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03 Sep 2020, 11:28
03 Sep 2020, 11:28
1
Carcass wrote:
Carol purchased one basket of fruit consisting of 4 Apples and 2 Oranges and another basket of fruit consisting of 3 Apples and 5 Oranges. Carol is to select one piece of fruit at random from each of the two baskets. What is the probability that one of the two pieces of fruit selected will be an apple and the other will be an orange?
(A) 1/4
(B) 1/2
(C) 1/24
(D) 5/24
(E) 13/24
(A) 1/4
(B) 1/2
(C) 1/24
(D) 5/24
(E) 13/24
Let's name the baskets!
Basket A has 4 Apples and 2 Oranges
Basket B has 3 Apples and 5 Oranges
P(1 of each type) = P(select apple from basket A AND orange from basket B OR select orange from basket A AND apple from basket B)
= [P(apple from basket A) x P(orange from basket B)] + [P(orange from basket A) x P(apple from basket B)]
= [4/6 x 5/8] + [2/6 x 3/8]
= 20/48 + 6/48
= 26/48
= 13/24
Answer: E
Cheers,
Brent
