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How much greater, in square inches, is the area of a square
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13 Sep 2020, 03:00
13 Sep 2020, 03:00
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Question Stats:
82% (01:04) correct
17% (01:03) wrong based on 17 sessions
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How much greater, in square inches, is the area of a square with a diagonal of 8 inches than the area of a square with a diagonal of 4 inches?
A. 4
B. 24
C. 32
D. 48
E. 96
A. 4
B. 24
C. 32
D. 48
E. 96
Re: How much greater, in square inches, is the area of a square
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14 Sep 2020, 21:54
14 Sep 2020, 21:54
2
we know that diagonal of square=√2*lenght of side
so L1=4√2 and L2=2√2
area of square 1=\((4√2)^2\)=32
area of square 2=\((2√2)^2\)=8
area of square 1 is greater than area of square 2 by 24(32-8)
option B is correct
so L1=4√2 and L2=2√2
area of square 1=\((4√2)^2\)=32
area of square 2=\((2√2)^2\)=8
area of square 1 is greater than area of square 2 by 24(32-8)
option B is correct
gmatclubot
Re: How much greater, in square inches, is the area of a square [#permalink]
14 Sep 2020, 21:54
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