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In the rectangle above, a – b > b – a.
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13 Sep 2020, 03:04
13 Sep 2020, 03:04
Expert Reply
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Question Stats:
56% (01:27) correct
43% (01:58) wrong based on 16 sessions
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GRE In the rectangle above.png [ 15.06 KiB | Viewed 2908 times ]
In the rectangle above, \(a – b > b – a\).
Quantity A |
Quantity B |
\( z^2-2x^2\) |
zero |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: In the rectangle above, a – b > b – a.
[#permalink]
13 Sep 2020, 03:19
13 Sep 2020, 03:19
1
As a-b>b-a
2a>2b
angle a>angle b
from property of triangle side opposite to greatest angle is longest side
so x>y
quant A =\(z^2-2x^2\) (as \(z^2=x^2+y^2\))
= \(y^2-x^2\)
so quant A will <0 (as x>y)
option B is correct
"if you like the explanation please press kudos please"
2a>2b
angle a>angle b
from property of triangle side opposite to greatest angle is longest side
so x>y
quant A =\(z^2-2x^2\) (as \(z^2=x^2+y^2\))
= \(y^2-x^2\)
so quant A will <0 (as x>y)
option B is correct
"if you like the explanation please press kudos please"
gmatclubot
Re: In the rectangle above, a – b > b – a. [#permalink]
13 Sep 2020, 03:19
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