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Re: Five sixth-grade classes are competing against one another i [#permalink]
Curious to know why A. I got D.
So my query is, the line says 'No class raised less than $ 60' --. means minimum 60, maximum even 200$?

So if I plug 1000$(one class raised 5 times as much as others), and others were at 200(4) --> the avg money raised is beyond $240

Please explain how I can interpret this better !
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Re: Five sixth-grade classes are competing against one another i [#permalink]
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Madhavi1990 wrote:
Curious to know why A. I got D.
So my query is, the line says 'No class raised less than $ 60' --. means minimum 60, maximum even 200$?

So if I plug 1000$(one class raised 5 times as much as others), and others were at 200(4) --> the avg money raised is beyond $240

Please explain how I can interpret this better !

When you say "the avg money raised is beyond $240," you're saying that Quantity A is greater than Quantity B.
So at this point, the correct answer is either A or D

In order to show that the correct answer is D, you must show that there's a possible case in which Quantity A is NOT greater than Quantity B.
You haven't done that.
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Re: Five sixth-grade classes are competing against one another i [#permalink]
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Minimum mean can be calculated when we have *4* classes raising at least $60.
Minimum any class raised is 60 and one class raised 5 times the combined amount collected by other 4 class.
So, 5*4*60= 1200 (minimum)

So, for all 5 sum total= 4 * 60 + 1200 = 1440
The least average we can expect, based on the conditions: 1440/5 = 288
Clearly, this is greater than 240.
So, the answer is: A
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Re: Five sixth-grade classes are competing against one another i [#permalink]
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Re: Five sixth-grade classes are competing against one another i [#permalink]
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