Last visit was: 18 Dec 2024, 12:15 It is currently 18 Dec 2024, 12:15

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
avatar
Intern
Intern
Joined: 14 Aug 2018
Posts: 9
Own Kudos [?]: 7 [0]
Given Kudos: 0
Send PM
avatar
Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
Own Kudos [?]: 2280 [0]
Given Kudos: 251
WE:Engineering (Energy and Utilities)
Send PM
avatar
Intern
Intern
Joined: 12 Sep 2020
Posts: 15
Own Kudos [?]: 9 [0]
Given Kudos: 0
Send PM
avatar
Intern
Intern
Joined: 25 Aug 2020
Posts: 17
Own Kudos [?]: 13 [0]
Given Kudos: 0
Send PM
Re: If x > y, then which of the following could be true? [#permalink]
1
The first scenario seems like it could never happen because it's a product of two X's and one y which will always be greater than the product of two y's and one x. This is due to the rule that x>y.

The second scenario fits because of the assumption we have made for the first scenario.

The third scenario can't work because of the fact that we know the product of two x's and one y is greater than the product of two y's and one x. On top of that it makes it negative. Even assuming x could be a negative integer, it still has no basis for them to equal eachother. Cheers!
Prep Club for GRE Bot
Re: If x > y, then which of the following could be true? [#permalink]
Moderators:
GRE Instructor
88 posts
GRE Forum Moderator
37 posts
Moderator
1115 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne