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The integers 1 through 5 are written on each of five cards.
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28 Sep 2020, 02:47
28 Sep 2020, 02:47
Expert Reply
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Question Stats:
56% (01:29) correct
44% (01:45) wrong based on 50 sessions
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The integers 1 through 5 are written on each of five cards. The cards are shuffled and one card is drawn at random. That card is then replaced, the cards are shuffled again and another card is drawn at random. This procedure is repeated one more time (for a total of three times). What is the probability that the sum of the numbers on the three cards drawn was 14 or 15?
A. 1/125
B. 2/125
C. 4/125
D. 1/25
E. 2/25
A. 1/125
B. 2/125
C. 4/125
D. 1/25
E. 2/25
Re: The integers 1 through 5 are written on each of five cards.
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28 Sep 2020, 02:47
28 Sep 2020, 02:47
Expert Reply
1
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Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
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Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
For more theory and practice see our GRE - Math Book
Re: The integers 1 through 5 are written on each of five cards.
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Updated on: 28 Sep 2020, 19:30
Updated on: 28 Sep 2020, 19:30
2
given events are mutually exclusive events
because outcome of sum getting 14 and 15 cannot happen at same time
so P(14 or 15)=P(14)+P(15)
P(14)=(3/125) (outcomes are (4,5,5) or (5,5,4) or (5,4,5))
P(15)=(1/125) (only one outcome (5,5,5)
so P(14 or 15)= (3/125)+(1/125)=4/125
option C is correct
because outcome of sum getting 14 and 15 cannot happen at same time
so P(14 or 15)=P(14)+P(15)
P(14)=(3/125) (outcomes are (4,5,5) or (5,5,4) or (5,4,5))
P(15)=(1/125) (only one outcome (5,5,5)
so P(14 or 15)= (3/125)+(1/125)=4/125
option C is correct
