for the big triangle ABC
sinB=(AC/BC)=(x+CF)/BC (x be each side of triangle)

now for small traingle BED
sinB=(ED/BE)=(x/BE)

both are equal
(x+CF)/BC=(x/BE)
(x+CF)=(BC/BE)*x
CF=x*((BC/BE)-1)
CF=x*(EC/BE) (BC=BE+EC)

as EC>BE (EC/BE)>1
CF=x*(some thing greater than one)
CF=AF*(some thing greater than one) (x is side of square)

so quant A > quant B

option A is correct

No sorry whatsoever.

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