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In the figure above, if the area of the smaller circular reg
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06 Oct 2020, 11:30
06 Oct 2020, 11:30
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67% (02:27) correct
32% (02:37) wrong based on 40 sessions
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In the figure above, if the area of the smaller circular region is \(\frac{1}{2}\) the area of the larger circular region, then the diameter of the larger circle is how many inches longer than the diameter of the smaller circle?
A. \(\sqrt{2}-1\)
B. \(\frac{1}{2}\)
C. \(\frac{\sqrt{2}}{2}\)
D. \(\frac{2-\sqrt{2}}{2}\)
E. \(\sqrt{2}\)
Re: In the figure above, if the area of the smaller circular reg
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06 Oct 2020, 20:12
06 Oct 2020, 20:12
1
area of small circle =(1/2)* area of large circle
area of large circle =\(π*(1/2)^2\)=π/4
area of small circle=π/8
diameter of small circle =1/(√2)
diameter of large circle is 1-1/(√2) times greater than small circle
option D is correct
area of large circle =\(π*(1/2)^2\)=π/4
area of small circle=π/8
diameter of small circle =1/(√2)
diameter of large circle is 1-1/(√2) times greater than small circle
option D is correct
Re: In the figure above, if the area of the smaller circular reg
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12 Oct 2020, 11:01
12 Oct 2020, 11:01
1
Assume the big area is 4 and small area will be 2
πr^2=4
r =2
Small circle
πr^2 =2
r =√2
Diameter is 2*r
Hence
Big diameter minus small diameter is
4-2√2
Divide thru by 4(my assumption for the area b4 )
1-2√2/2
LCM will get (2-√2)/2
Ans D
Posted from my mobile device
πr^2=4
r =2
Small circle
πr^2 =2
r =√2
Diameter is 2*r
Hence
Big diameter minus small diameter is
4-2√2
Divide thru by 4(my assumption for the area b4 )
1-2√2/2
LCM will get (2-√2)/2
Ans D
Posted from my mobile device
