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s and t are positive integers greater than 1.
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07 Oct 2020, 09:55
07 Oct 2020, 09:55
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75% (01:06) correct
25% (00:45) wrong based on 92 sessions
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s and t are positive integers greater than 1.
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(s^{\frac{1}{4}}\) |
\(s^{t-4}\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
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Re: s and t are positive integers greater than 1.
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07 Oct 2020, 10:35
07 Oct 2020, 10:35
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Carcass wrote:
s and t are positive integers greater than 1.
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(s^{\frac{1}{4}}\) |
\(s^{t-4}\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Let's test some possible values of x and y
case i: Since s and t are positive integers greater than 1, one possible pair of values is s = 16 and t = 4
We get:
Quantity A: \(s^{\frac{1}{4}} = 16^{\frac{1}{4}} = 2\)
Quantity B: \(s^{t-4}=16^{4-4}=16^{0}=1\)
In this case, Quantity A is greater
case ii: Another possible pair of values is s = 16 and t = 5
We get:
Quantity A: \(s^{\frac{1}{4}} = 16^{\frac{1}{4}} = 2\)
Quantity B: \(s^{t-4}=16^{5-4}=16^{1}=16\)
In this case, Quantity B is greater
Answer: D
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Re: s and t are positive integers greater than 1.
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27 Nov 2020, 00:40
27 Nov 2020, 00:40
I multiplied s^4 to both sides and got 1 as Quantity A and s^t as Quantity B.
Where did I go wrong?
EDIT: Oh, I saw the first quantity as 1/s^4 and not s^(1/4) ..
Where did I go wrong?
EDIT: Oh, I saw the first quantity as 1/s^4 and not s^(1/4) ..
