Let's test some possible values of x and y

case i: Since s and t are positive integers greater than 1, one possible pair of values is s = 16 and t = 4
We get:
Quantity A: \(s^{\frac{1}{4}} = 16^{\frac{1}{4}} = 2\)
Quantity B: \(s^{t-4}=16^{4-4}=16^{0}=1\)
In this case, Quantity A is greater


case ii: Another possible pair of values is s = 16 and t = 5
We get:
Quantity A: \(s^{\frac{1}{4}} = 16^{\frac{1}{4}} = 2\)
Quantity B: \(s^{t-4}=16^{5-4}=16^{1}=16\)
In this case, Quantity B is greater

Answer: D

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