GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure above, if the area of the smaller circular reg
[#permalink]
06 Oct 2020, 11:30
06 Oct 2020, 11:30
Expert Reply
00:00
Question Stats:
69% (02:27) correct
30% (02:21) wrong based on 39 sessions
Hide Show timer Statistics
Attachment:
GRE In the figure above, if the area of the smaller.png [ 11.13 KiB | Viewed 1905 times ]
In the figure above, if the area of the smaller circular region is \(\frac{1}{2}\) the area of the larger circular region, then the diameter of the larger circle is how many inches longer than the diameter of the smaller circle?
A. \(\sqrt{2}-1\)
B. \(\frac{1}{2}\)
C. \(\frac{\sqrt{2}}{2}\)
D. \(\frac{2-\sqrt{2}}{2}\)
E. \(\sqrt{2}\)
Re: In the figure above, if the area of the smaller circular reg
[#permalink]
06 Oct 2020, 20:12
06 Oct 2020, 20:12
1
area of small circle =(1/2)* area of large circle
area of large circle =\(π*(1/2)^2\)=π/4
area of small circle=π/8
diameter of small circle =1/(√2)
diameter of large circle is 1-1/(√2) times greater than small circle
option D is correct
area of large circle =\(π*(1/2)^2\)=π/4
area of small circle=π/8
diameter of small circle =1/(√2)
diameter of large circle is 1-1/(√2) times greater than small circle
option D is correct
Re: In the figure above, if the area of the smaller circular reg
[#permalink]
12 Oct 2020, 11:01
12 Oct 2020, 11:01
1
Assume the big area is 4 and small area will be 2
πr^2=4
r =2
Small circle
πr^2 =2
r =√2
Diameter is 2*r
Hence
Big diameter minus small diameter is
4-2√2
Divide thru by 4(my assumption for the area b4 )
1-2√2/2
LCM will get (2-√2)/2
Ans D
Posted from my mobile device
πr^2=4
r =2
Small circle
πr^2 =2
r =√2
Diameter is 2*r
Hence
Big diameter minus small diameter is
4-2√2
Divide thru by 4(my assumption for the area b4 )
1-2√2/2
LCM will get (2-√2)/2
Ans D
Posted from my mobile device
