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A graph of the function g(x) is shown above. g(x) is defined
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12 Oct 2020, 10:08
12 Oct 2020, 10:08
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Question Stats:
46% (00:58) correct
53% (01:17) wrong based on 39 sessions
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Attachment:
GRE A graph of the function.png [ 17.69 KiB | Viewed 3679 times ]
A graph of the function \(g(x)\) is shown above. \(g(x)\) is defined by which of the following equations?
A. \(g(x)=(x+1)^2-2\)
B. \(g(x)=(x-1)^2-2\)
C. \(g(x)=(x+1)^2+2\)
D. \(g(x)=(x-1)^2+2\)
E. \(g(x)=(x-2)^2+1\)
Kudos for the right answer and explanation
Re: A graph of the function g(x) is shown above. g(x) is defined
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16 Oct 2020, 00:29
16 Oct 2020, 00:29
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Quote:
A graph of the function g(x) is shown above. g(x) is defined by which of the following equations?
Step 1: Understanding the question
Vertex form of the Quadratic equation is a\((x-h)^2\) + k = 0, where (h,k) are the coordinates of the vertex.
Step 2: Calculation
refer to the attachment
Value of the vertex (h,k) = (1,-2)
Hence quadratic equation is a\((x-1)^2\) - 2 = 0
As value of a = 1, as per the options
B is correct
Attachments
GRE A graph of the function (1).png [ 21.7 KiB | Viewed 3492 times ]
Re: A graph of the function g(x) is shown above. g(x) is defined
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16 Oct 2020, 05:32
16 Oct 2020, 05:32
1
The given function g(x)
If we plugin values of x in the functions only option B function satisfy the graph
\(g(x) = (x-1)^2 - 2\)
Let, x=0
Plugin the value of x=0 in the function
\(g(0)=(0-1)^2 - 2= -1\)
x=1
\(g(1)=(1-1)^2 - 2= -2\)
x= -0.42
\(g(-.42)=g(-.42-1)^2 - 2=0\)
So, only option B satisfy the graph of the curve(parabola) with vertex @ (1,-2)
Option B
If we plugin values of x in the functions only option B function satisfy the graph
\(g(x) = (x-1)^2 - 2\)
Let, x=0
Plugin the value of x=0 in the function
\(g(0)=(0-1)^2 - 2= -1\)
x=1
\(g(1)=(1-1)^2 - 2= -2\)
x= -0.42
\(g(-.42)=g(-.42-1)^2 - 2=0\)
So, only option B satisfy the graph of the curve(parabola) with vertex @ (1,-2)
Option B
