GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A graph of the function g(x) is shown above. g(x) is defined
[#permalink]
12 Oct 2020, 10:08
12 Oct 2020, 10:08
1
Expert Reply
2
Bookmarks
00:00
Question Stats:
53% (01:03) correct
46% (01:16) wrong based on 47 sessions
Hide Show timer Statistics
Attachment:
GRE A graph of the function.png [ 17.69 KiB | Viewed 4996 times ]
A graph of the function \(g(x)\) is shown above. \(g(x)\) is defined by which of the following equations?
A. \(g(x)=(x+1)^2-2\)
B. \(g(x)=(x-1)^2-2\)
C. \(g(x)=(x+1)^2+2\)
D. \(g(x)=(x-1)^2+2\)
E. \(g(x)=(x-2)^2+1\)
Kudos for the right answer and explanation
Re: A graph of the function g(x) is shown above. g(x) is defined
[#permalink]
16 Oct 2020, 00:29
16 Oct 2020, 00:29
1
1
Bookmarks
Quote:
A graph of the function g(x) is shown above. g(x) is defined by which of the following equations?
Step 1: Understanding the question
Vertex form of the Quadratic equation is a\((x-h)^2\) + k = 0, where (h,k) are the coordinates of the vertex.
Step 2: Calculation
refer to the attachment
Value of the vertex (h,k) = (1,-2)
Hence quadratic equation is a\((x-1)^2\) - 2 = 0
As value of a = 1, as per the options
B is correct
Attachments
GRE A graph of the function (1).png [ 21.7 KiB | Viewed 4816 times ]
Re: A graph of the function g(x) is shown above. g(x) is defined
[#permalink]
16 Oct 2020, 05:32
16 Oct 2020, 05:32
1
The given function g(x)
If we plugin values of x in the functions only option B function satisfy the graph
\(g(x) = (x-1)^2 - 2\)
Let, x=0
Plugin the value of x=0 in the function
\(g(0)=(0-1)^2 - 2= -1\)
x=1
\(g(1)=(1-1)^2 - 2= -2\)
x= -0.42
\(g(-.42)=g(-.42-1)^2 - 2=0\)
So, only option B satisfy the graph of the curve(parabola) with vertex @ (1,-2)
Option B
If we plugin values of x in the functions only option B function satisfy the graph
\(g(x) = (x-1)^2 - 2\)
Let, x=0
Plugin the value of x=0 in the function
\(g(0)=(0-1)^2 - 2= -1\)
x=1
\(g(1)=(1-1)^2 - 2= -2\)
x= -0.42
\(g(-.42)=g(-.42-1)^2 - 2=0\)
So, only option B satisfy the graph of the curve(parabola) with vertex @ (1,-2)
Option B
