GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
No of 3 digit passwords that can be formed using different
[#permalink]
Updated on: 23 Oct 2020, 09:55
Updated on: 23 Oct 2020, 09:55
1
3
Bookmarks
00:00
Question Stats:
35% (01:42) correct
64% (01:11) wrong based on 39 sessions
Hide Show timer Statistics
Quantity A |
Quantity B |
No of 3 digit passwords that can be formed using different digits from 1, 2, 3, 4, 5, so that the digits are in increasing order from left to right |
10 |
a. Quantity A is greater.
b. Quantity B is greater.
c. The two quantities are equal.
d. The relationship cannot be determined from the information given.
Originally posted by arunkumarzz on 23 Oct 2020, 08:49.
Last edited by Carcass on 23 Oct 2020, 09:55, edited 2 times in total.
Last edited by Carcass on 23 Oct 2020, 09:55, edited 2 times in total.
Formatted
Re: No of 3 digit passwords that can be formed using different
[#permalink]
23 Oct 2020, 09:07
23 Oct 2020, 09:07
2
I don't know if there is a faster way to solve this problem, but here is I how I solved it:
Divide into cases:
First two numbers are 1 and 2.
There are three possible numbers for the third number (3,4,5). We have 3 cases here.
First two numbers are 1 and 3:
There are two possible numbers for the third number(4,5). We have 2 cases here.
First two numbers are 1 and 4:
Just one possible number for the third number(5). 1 case
First two numbers are 2 and 3:
Two possible numbers for the third number (4,5). 2 cases
First two numbers are 2 and 4:
Just one possible number for the third number (5). 1 case
The last case is the first is formed by the sequence 3-4-5.
We have 3+2+1+2+1+1=10 possibilities. Answer is C
Divide into cases:
First two numbers are 1 and 2.
There are three possible numbers for the third number (3,4,5). We have 3 cases here.
First two numbers are 1 and 3:
There are two possible numbers for the third number(4,5). We have 2 cases here.
First two numbers are 1 and 4:
Just one possible number for the third number(5). 1 case
First two numbers are 2 and 3:
Two possible numbers for the third number (4,5). 2 cases
First two numbers are 2 and 4:
Just one possible number for the third number (5). 1 case
The last case is the first is formed by the sequence 3-4-5.
We have 3+2+1+2+1+1=10 possibilities. Answer is C
Re: No of 3 digit passwords that can be formed using different
[#permalink]
23 Oct 2020, 09:56
23 Oct 2020, 09:56
1
Expert Reply
Please, Please, follow the rules how to format a question: QCQ
It is very easy and took one second
https://gre.myprepclub.com/forum/how-to-po ... 12752.html
It is very easy and took one second
https://gre.myprepclub.com/forum/how-to-po ... 12752.html
