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−1 < x < y < 0
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26 Oct 2020, 02:23
26 Oct 2020, 02:23
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94% (00:47) correct
6% (00:39) wrong based on 50 sessions
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\(−1 < x < y < 0 \)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Source: 320 GRE Math Questions
Quantity A |
Quantity B |
\(x+y\) |
\(x^2+y^2\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Source: 320 GRE Math Questions
Re: −1 < x < y < 0
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26 Oct 2020, 05:49
26 Oct 2020, 05:49
We have both x and y less than 0, so x+y will be less than 0 too. Quantity A is less than 0.
For quantity B, since \(x <0 \) and \(y<0\) we have \(x^2>0\) and \(y^2>0\). Therefore quantity B>0.
So B>A and answer is B.
For quantity B, since \(x <0 \) and \(y<0\) we have \(x^2>0\) and \(y^2>0\). Therefore quantity B>0.
So B>A and answer is B.
Re: 1 < x < y < 0
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23 Mar 2026, 11:05
23 Mar 2026, 11:05
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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