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Joe, Mike, Phil, John and Fred own a total of 138 CDs. If Jo
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26 Oct 2020, 02:13
26 Oct 2020, 02:13
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Joe, Mike, Phil, John and Fred own a total of 138 CDs. If John owns 38 of them, what is the average (arithmetic mean) number of CDs owned by Joe, Mike, Phil and Fred?
A. 10
B. 15
C. 20
D. 25
E. 30
Source: 320 GRE Math Questions
A. 10
B. 15
C. 20
D. 25
E. 30
Source: 320 GRE Math Questions
Re: Joe, Mike, Phil, John and Fred own a total of 138 CDs. If Jo
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26 Oct 2020, 02:24
26 Oct 2020, 02:24
1
Here,
Number of John's CDs = 38
Joe + Mike + Phil + John + Fred = 138
So we can subtract John's CDs from both side:
Joe + Mike + Phil + Fred = 138 - 38 = 100
Average(arithmetic mean) of Joe, Mike, Phil and Fred's CDs:
\(\frac{Joe + Mike + Phil + Fred}{4}\) = \(\frac{100}{4}\) = 25
Answer : D
Number of John's CDs = 38
Joe + Mike + Phil + John + Fred = 138
So we can subtract John's CDs from both side:
Joe + Mike + Phil + Fred = 138 - 38 = 100
Average(arithmetic mean) of Joe, Mike, Phil and Fred's CDs:
\(\frac{Joe + Mike + Phil + Fred}{4}\) = \(\frac{100}{4}\) = 25
Answer : D
Re: Joe, Mike, Phil, John and Fred own a total of 138 CDs. If Jo
[#permalink]
04 Sep 2024, 10:25
04 Sep 2024, 10:25
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