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−1 < x < y < 0

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−1 < x < y < 0 [#permalink] New post   26 Oct 2020, 02:23
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\(−1 < x < y < 0 \)



Quantity A
Quantity B
\(x+y\)
\(x^2+y^2\)




A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Source: 320 GRE Math Questions
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B
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rcpacheco
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Re: −1 < x < y < 0 [#permalink] New post   26 Oct 2020, 05:49
We have both x and y less than 0, so x+y will be less than 0 too. Quantity A is less than 0.

For quantity B, since \(x <0 \) and \(y<0\) we have \(x^2>0\) and \(y^2>0\). Therefore quantity B>0.
So B>A and answer is B.
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Re: 1 < x < y < 0 [#permalink] New post   21 Apr 2023, 07:19
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: 1 < x < y < 0 [#permalink]
21 Apr 2023, 07:19
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