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If a#b = a2 – a, where b ≥ 0, what is the value of (–4)#4? (
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27 Jul 2018, 07:00
27 Jul 2018, 07:00
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Question Stats:
84% (00:32) correct
15% (00:50) wrong based on 69 sessions
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If \(a\sharp b = a^2\sqrt{b} - a\), where \(b ≥ 0\), what is the value of \((–4)\sharp 4\)?
(A) –36
(B) –28
(C) 12
(D) 28
(E) 36
(A) –36
(B) –28
(C) 12
(D) 28
(E) 36
Re: If a#b = a2 – a, where b ≥ 0, what is the value of (–4)#4? (
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12 Aug 2018, 04:54
12 Aug 2018, 04:54
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Expert Reply
Explanation
This problem defines a function for the made-up symbol #.
In this problem a = (–4) and b = 4.
Plug the values into the function: \((-4)^2 \sqrt{4}- (-4) = 16 \times 2 + 4 = 36\).
Do not forget to keep the parentheses around the –4!
Also note that only the positive root of 4 applies, because the problem has been presented in the form of a real number underneath the square root sign.
This problem defines a function for the made-up symbol #.
In this problem a = (–4) and b = 4.
Plug the values into the function: \((-4)^2 \sqrt{4}- (-4) = 16 \times 2 + 4 = 36\).
Do not forget to keep the parentheses around the –4!
Also note that only the positive root of 4 applies, because the problem has been presented in the form of a real number underneath the square root sign.
Re: If a#b = a2 – a, where b ≥ 0, what is the value of (–4)#4? (
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08 Jan 2020, 16:49
08 Jan 2020, 16:49
Expert Reply
Updated the question
