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p is the probability that a school’s hockey team wins today.
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17 Nov 2020, 04:32
17 Nov 2020, 04:32
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Question Stats:
76% (00:42) correct
23% (01:10) wrong based on 101 sessions
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p is the probability that a school’s hockey team wins today.
s is the independent probability that the school’s lacrosse team wins today.
p and s are not both equal to 0.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for the right solution and explanation
s is the independent probability that the school’s lacrosse team wins today.
p and s are not both equal to 0.
Quantity A |
Quantity B |
p+s |
ps |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for the right solution and explanation
Re: p is the probability that a school’s hockey team wins today.
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18 Nov 2020, 00:12
18 Nov 2020, 00:12
2
not p and s are not both zero=> one at least zero,
probability can be negative, thus
A here is always greater than B (A is the answer)
probability can be negative, thus
A here is always greater than B (A is the answer)
Re: p is the probability that a schools hockey team wins today.
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23 Aug 2025, 17:33
23 Aug 2025, 17:33
*p=0.5, s=0.5:
p+s=1.0 y ps=0.25 → 1.0>0.25
*p=0.8, s=0.2:
p+s=1.0 y ps=0.16 → 1.0>0.16
Notice that p+s>ps (they would only be equal if p=s=0, which is excluded)
Therefore, the answer is A: Quantity A is greater.
p+s=1.0 y ps=0.25 → 1.0>0.25
*p=0.8, s=0.2:
p+s=1.0 y ps=0.16 → 1.0>0.16
Notice that p+s>ps (they would only be equal if p=s=0, which is excluded)
Therefore, the answer is A: Quantity A is greater.
