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The cost of ten hot dogs and nine pretzels is $74.15. The co
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17 Nov 2020, 07:33
17 Nov 2020, 07:33
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87% (01:32) correct
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The cost of ten hot dogs and nine pretzels is $74.15.
The cost of nine hot dogs and ten pretzels is $74.05.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for the right solution and explanation
The cost of nine hot dogs and ten pretzels is $74.05.
Quantity A |
Quantity B |
The cost of one hot dog |
The cost of one pretzel |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for the right solution and explanation
Re: The cost of ten hot dogs and nine pretzels is $74.15. The co
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17 Nov 2020, 11:18
17 Nov 2020, 11:18
1
Carcass wrote:
The cost of ten hot dogs and nine pretzels is $74.15.
The cost of nine hot dogs and ten pretzels is $74.05.
The cost of nine hot dogs and ten pretzels is $74.05.
a) 10h + 9p = 74.15
b) 9h + 10p = 74.05
Multiply equation a by 9 and equation b by 10
We will get
a) 90h + 81p = 667.35
b) 90h + 100p = 740.5
Subtract a from b => b-a
We get 19p = 73.15
Therefore p = 3.85
Substitute value of p in the equation a or b, we will get h = 3.95
Hence, Answer is A.
Re: The cost of ten hot dogs and nine pretzels is $74.15. The co
[#permalink]
17 Nov 2020, 22:48
17 Nov 2020, 22:48
1
Carcass wrote:
The cost of ten hot dogs and nine pretzels is $74.15.
The cost of nine hot dogs and ten pretzels is $74.05.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for the right solution and explanation
The cost of nine hot dogs and ten pretzels is $74.05.
Quantity A |
Quantity B |
The cost of one hot dog |
The cost of one pretzel |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for the right solution and explanation
Let hot dogs be h and pretzels be p.
10h + 9p = 74.15 ==> h = (74.15-9p)/10 = 7.415-0.9p
Substitute h in 9h + 10p = 74.05 ==> 9(7.415-0.9p) + 10p = 74.05.
66.735 - 8.1p + 10p = 74.05.
1.9p = 7.315 ==> p = 7.315/1.9 = 3.85.
Substitute p value in 9h + 10p = 74.05.
9h + 10(3.85) = 74.05 ==> 9h = 74.05 - 38.5 ==> 9h = 35.55 ==> h = 3.95.
Cost of one pretzel, which is $3.85 is less than cost of one hot dog which is $3.95, so Qty A is the correct answer.
