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At 12:00, noon, a pool is full. It is being filled at a cons
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18 Nov 2020, 10:07
18 Nov 2020, 10:07
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Question Stats:
86% (02:14) correct
13% (02:06) wrong based on 68 sessions
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At 12:00, noon, a pool is \(\frac{3}{25}\) full. It is being filled at a constant rate of 2 gallons per minute. At 2:30 PM, the pool is 28% full. How many gallons does the full pool hold?
A. 1,875
B. 1,925
C. 1,975
D. 2,025
E. 2,075
Kudos for the right solution and explanation
A. 1,875
B. 1,925
C. 1,975
D. 2,025
E. 2,075
Kudos for the right solution and explanation
Re: At 12:00, noon, a pool is full. It is being filled at a cons
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18 Nov 2020, 12:21
18 Nov 2020, 12:21
2
At 2:30 the pool is 28% full which is 7/25
7/25-3/25=4/25(number of pool filled within 12-2:30)
It means 2*150(12 to 2:30(2hrs 30mins))
4/25=300
Then the full pool is 4/25*x=300
X =1875 A
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7/25-3/25=4/25(number of pool filled within 12-2:30)
It means 2*150(12 to 2:30(2hrs 30mins))
4/25=300
Then the full pool is 4/25*x=300
X =1875 A
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Re: At 12:00, noon, a pool is full. It is being filled at a cons
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19 Nov 2020, 11:30
19 Nov 2020, 11:30
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We may would like to reduce calculation efforts like this one.
At noon , 3/25 = 12/100
At 2:30 pm ,150 minutes later from noon, 28 % full = 28/100
By supplying water for 150 minutes, we can fill (28-12)/100 = 16/100
To fill the pool we need to calculate X.
X = (100/16) * 150 * 2
= (100/16) * 300
= 100 * (300/16)
We may be able to calculate below without paper nor pencil.
Y= 300/16
= 18.????
??? part, we do not have to calculate.
What we calculate is 100 * Y and only choice is A. 1,875
At noon , 3/25 = 12/100
At 2:30 pm ,150 minutes later from noon, 28 % full = 28/100
By supplying water for 150 minutes, we can fill (28-12)/100 = 16/100
To fill the pool we need to calculate X.
X = (100/16) * 150 * 2
= (100/16) * 300
= 100 * (300/16)
We may be able to calculate below without paper nor pencil.
Y= 300/16
= 18.????
??? part, we do not have to calculate.
What we calculate is 100 * Y and only choice is A. 1,875
