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If xn is different from zero
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16 Jan 2020, 10:15
16 Jan 2020, 10:15
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Question Stats:
58% (01:12) correct
41% (01:08) wrong based on 93 sessions
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\(xn \neq 0
\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
\)
Quantity A |
Quantity B |
\(\frac{ x}{n}\) |
\(\frac{\frac{4}{n}}{\frac{1}{3x} + \frac{5}{x}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: If xn is different from zero
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05 Feb 2020, 11:40
05 Feb 2020, 11:40
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Carcass wrote:
\(xn \neq 0
\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
\)
Quantity A |
Quantity B |
\(\frac{ x}{n}\) |
\(\frac{\frac{4}{n}}{\frac{1}{3x} + \frac{5}{x}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
The quantity B is simplified to \(\frac{3}{4}* \frac{x}{n}\)
Then you need to compare \(\frac{x}{n}\) vs \(\frac{3}{4}* \frac{x}{n}\)
Since \(xn \neq 0\) we can assume both x = 1 and n = 1 then quantity A is bigger (1>3/4) but when x = 1 and n= -1 then B>A (-1<-3/4). The answer is D.
Re: If xn is different from zero
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23 Nov 2020, 11:51
23 Nov 2020, 11:51
1
I plugged in and the only reason it is worth mentioning at all is that this problem provides a good example of when to start by plugging in 'weird' numbers. Choose 1/3 for X for example and 1/6 for n. Just a reminder for those of us who have done so many problems and plugged in so many times that we might forget that one of the major reasons to plug in (another being to get more info especially on a quant comp, must be or could be ?) is to make the problem simpler.
