Carcass wrote:
\(3x - 4y = -12 \)
\(6x + 2y = 36\)
Quantity A |
Quantity B |
x |
y |
Given:
Quantity A: \(3x - 4y = -12 \)
Quantity B: \(6x + 2y = 36\)
Take the bottom equation and divide both sides by 2 to get an equivalent equation:
Quantity A: \(3x - 4y = -12 \)
Quantity B: \(3x + y = 18\)
Subtract at the bottom equation from the top equation to get: \(-5y = -30\)
Solve: \(y = 6\)
Find the value of x, take any of the given equations and replace \(y\) with \(6\).
For example, take: \(3x - 4y = -12 \)
Substitute to get: \(3x - 4(6) = -12 \)
Simplify: \(3x - 24 = -12 \)
Add 24 to both sides: \(3x = 12 \)
Solve: x = 4
So, we have:
Quantity A: \(4 \)
Quantity B: \(6\)
Answer: B