GreenlightTestPrep wrote:
How many liters of a solution that is 15 percent salt must be added to 5 liters of a solution that is 8 percent salt so that the resulting solution is 10 percent salt?
We have 5 liters of solution with 8% salt.
We also have unlimited quantity of solution with 15% salt.
The question asks us to add x liters of solution with 15% salt to 5 liters of solution with 8% salt to make it x+5 liters of solution with 10% salt.
15% of x liters + 8% of 5 liters = 10% of (5 + x) liters.
0.15x + 0.08(5) = 0.10(5+x) --> 0.15x + 0.40 = 0.50 + 0.10x.
0.05x = 0.10 --> x = 2.
Therefore 2 liters of solution with 15% salt has to be added to make a 7 liter solution with 10% salt.