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When positive integer x is divided by positive integer y
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10 Nov 2020, 05:43
10 Nov 2020, 05:43
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73% (01:12) correct
26% (01:46) wrong based on 41 sessions
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When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?
(A) 96
(B) 75
(C) 48
(D) 25
(E) 12
(A) 96
(B) 75
(C) 48
(D) 25
(E) 12
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Joined: 14 Jul 2020
Posts: 3
Given Kudos: 0
GRE 1: Q170 V158
Re: Divisibility
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10 Nov 2020, 08:48
10 Nov 2020, 08:48
1
\(x = y * q + r\)
where q is the quotient and r is the remainder
dividing by y on both sides
\(x/y = q + r/y\)
we know what \(x/y\) is and as q is always non negative and \(r/y \)is less than 1
so \(96.12 = 96 + 9/y\)
\(0.12 = 9/y\)
Hence\( y = 75\)
where q is the quotient and r is the remainder
dividing by y on both sides
\(x/y = q + r/y\)
we know what \(x/y\) is and as q is always non negative and \(r/y \)is less than 1
so \(96.12 = 96 + 9/y\)
\(0.12 = 9/y\)
Hence\( y = 75\)
Re: When positive integer x is divided by positive integer y
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11 Nov 2020, 13:46
11 Nov 2020, 13:46
2
daina1323031 wrote:
When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?
(A) 96
(B) 75
(C) 48
(D) 25
(E) 12
(A) 96
(B) 75
(C) 48
(D) 25
(E) 12
The first part of the question can be written as x/y = ANS + 9/y, where "ANS" is our unknown quotient. The second part can be written as x/y = 96 + 12/100. Thus we know that our unknown answer from the first part of the question is 96, so we are left with x/y = 96 + 9/y = 96 + 12/100. Set 9/y equal to 12/100 and solve for y: you are left with y = 75. Answer choice B is correct.
