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If the inside diameter of a cylindrical garden hose is 1 inc
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11 Dec 2020, 22:25
11 Dec 2020, 22:25
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If the inside diameter of a cylindrical garden hose is 1 inch, what is the length, in inches, of a straight hose that can hold a maximum of 1 gallon of water? (1 gallon = 231 cubic inches)
A. \(231\pi\)
B. \(\frac{231}{\pi}\)
C. \(924\)
D. \(924\pi\)
E. \(\frac{924}{\pi}\)
A. \(231\pi\)
B. \(\frac{231}{\pi}\)
C. \(924\)
D. \(924\pi\)
E. \(\frac{924}{\pi}\)
Re: If the inside diameter of a cylindrical garden hose is 1 inc
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12 Dec 2020, 05:18
12 Dec 2020, 05:18
1
Carcass wrote:
If the inside diameter of a cylindrical garden hose is 1 inch, what is the length, in inches, of a straight hose that can hold a maximum of 1 gallon of water? (1 gallon = 231 cubic inches)
A. \(231\pi\)
B. \(\frac{231}{\pi}\)
C. \(924\)
D. \(924\pi\)
E. \(\frac{924}{\pi}\)
A. \(231\pi\)
B. \(\frac{231}{\pi}\)
C. \(924\)
D. \(924\pi\)
E. \(\frac{924}{\pi}\)
Explanation:
This is straight forward question,
We know, Volume of cylinder =\( \pi * radius^2 *Height
\)
therefore,
231 = \(\pi * ({\frac{1}{2}})^2 * Height\)
or height (length of the hose) = \(\frac{{231 * 4}}{{\pi}}\)
Re: If the inside diameter of a cylindrical garden hose is 1 inc
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17 Dec 2020, 19:31
17 Dec 2020, 19:31
231 cubic inches is the volume we(re trying to get to.
The volume of a cylinder is just the area of the top multiplied by its length, What's the length?
Well... pi (1/2)^2 * l = 231 ==> (231/pi)*4 = l = 924/pi.
The volume of a cylinder is just the area of the top multiplied by its length, What's the length?
Well... pi (1/2)^2 * l = 231 ==> (231/pi)*4 = l = 924/pi.
