Re: If (x-1)^2=(x-2)^2, then x=
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03 Jan 2024, 00:38
if \((x-1)^ = (x-2)^2\) then,
expanding both sides of the equation, we get
\(x^2 + 1^2 - 2\times 1\times x = x^2 + 2^2 - 2\times 2 \times x\)
\(x^2 + 1 - 2x = x^2 + 4 - 4x\)
cancelling like terms on both sides and rearranging,
\(2x - 3 = 0\)
\(2x = 3\)
\(x = \frac{3}{2}\)