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A mixture contains nothing but water and acetone in a ratio

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Asmakan
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A mixture contains nothing but water and acetone in a ratio [#permalink] New post   Updated on: 19 Dec 2020, 09:48
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A mixture contains nothing but water and acetone in a ratio of 1:2. After 200 mL of water is added to the mixture, the ratio of water to acetone is 2:3.

Quantity A
Quantity B
The original volume of the mixture
1800mL


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Official Answer
C

Originally posted by Asmakan on 19 Dec 2020, 08:57.
Last edited by Carcass on 19 Dec 2020, 09:48, edited 1 time in total.
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Asmakan
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Re: A mixture contains [#permalink] New post   19 Dec 2020, 08:59
I solve it this way:
May someone clarifies were is the mistake :
1)water to Acetone 1:2
2) after addition 2:3

for water :
so , x+200= 2x
x= 200
then multiply to 3* 200= 600

but wrong. Where is the mistake?
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Carcass
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Re: A mixture contains nothing but water and acetone in a ratio [#permalink] New post   19 Dec 2020, 10:05
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There is no need of calculation but just reasoning and looking at the proportion

At first w/a was 1/2

After 200 water which is even and which is the double of 100%, so we do have an arithmetic progression

The new ration is 2/3 or could be 4/6 or 8/12 and so forth


C must be the answer
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GreenlightTestPrep
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Re: A mixture contains [#permalink] New post   19 Dec 2020, 11:16
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Asmakan wrote:
I solve it this way:
May someone clarifies were is the mistake :
1)water to Acetone 1:2
2) after addition 2:3

for water :
so , x+200= 2x
x= 200
then multiply to 3* 200= 600

but wrong. Where is the mistake?


What does the variable x represent In your solution?
It will help you understand the flaw here: x+200= 2x
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eldorado21
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Re: A mixture contains nothing but water and acetone in a ratio [#permalink] New post   19 Dec 2020, 19:46
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@Asmakan

x+200 not= 2x ; this is because 2 is part of a ratio.

x = volume of water.
After adding 200 mL of water
x+200/2x = 2/3

x = 600; 2x = 1200;

So original volume of solution = 600 + 1200 = 1800
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Asmakan
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Re: A mixture contains [#permalink] New post   19 Dec 2020, 22:29
GreenlightTestPrep wrote:
Asmakan wrote:
I solve it this way:
May someone clarifies were is the mistake :
1)water to Acetone 1:2
2) after addition 2:3

for water :
so , x+200= 2x
x= 200
then multiply to 3* 200= 600

but wrong. Where is the mistake?


What does the variable x represent In your solution?
It will help you understand the flaw here: x+200= 2x


x here represents the multiplier in the second ratio.
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Asmakan
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Re: A mixture contains nothing but water and acetone in a ratio [#permalink] New post   19 Dec 2020, 22:35
Carcass wrote:
There is no need of calculation but just reasoning and looking at the proportion

At first w/a was 1/2

After 200 water which is even and which is the double of 100%, so we do have an arithmetic progression

The new ration is 2/3 or could be 4/6 or 8/12 and so forth


C must be the answer


100% because 1 became 2 ? or what?
you realized the Arithmatic progression because 1 became 2 and 2 became 3?
May please clarify your explanation more?
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RAMJAN
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A mixture contains nothing but water and acetone in a ratio [#permalink] New post   23 Nov 2021, 14:01
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RAMJAN
(X+200)/2X = 2/3
3X+600 = 4X
X = 600;
So that, original volume is 600 + (2*600) = 1800
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motion2020
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A mixture contains nothing but water and acetone in a ratio [#permalink] New post   24 Nov 2021, 19:43
1
original volume is x
water is \(x*\frac{1}{(1+2)}\)=\(x/3\)

\((x/3 + 200)/(x+200)\)=\(\frac{2}{(2+3)}\)
\(5x/3+1000=2x+400\)
\(5x+3000=6x+1200\)
\(x=1800\) is the required original volume in Quantity A

Answer is C

Asmakan wrote:
A mixture contains nothing but water and acetone in a ratio of 1:2. After 200 mL of water is added to the mixture, the ratio of water to acetone is 2:3.

Quantity A
Quantity B
The original volume of the mixture
1800mL


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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motion2020
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A mixture contains nothing but water and acetone in a ratio [#permalink] New post   24 Nov 2021, 19:56
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Also, you could use alligation method for mixtures

|2/5-1/3| / |2/5 - 1| = 200/x,

1/9=200/x and x=1800, where x stands for original volume
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Re: A mixture contains nothing but water and acetone in a ratio [#permalink] New post   09 Jun 2022, 23:27
2
Given,
Water : Acetone = 1:2
Original Volume =1x+2x
Now added 200 ml of water, then
(1x+200)/2x=2/3
x=600
Original Volume=600+1200=1800 Answer (C)
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pinkpanthermath
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Re: A mixture contains nothing but water and acetone in a ratio [#permalink] New post   20 May 2025, 21:24
1
very simple equation.

1/3 x + 200 = 2/5(200+x)

Where x is simply the volume of original sol.

Solving the above will give x=1800
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Re: A mixture contains nothing but water and acetone in a ratio [#permalink]
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