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If 2a + 2b = 7 and 3c + 3d = 15, then the average (arithmeti
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26 Dec 2020, 03:31
26 Dec 2020, 03:31
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Question Stats:
77% (01:13) correct
22% (00:19) wrong based on 18 sessions
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If \(2a + 2b = 7\) and \(3c + 3d = 15\), then the average (arithmetic mean) of a, b, c, and d is
A. \(1 \frac{1}{2}\)
B. \(2 \frac{1}{8}\)
C. \(3\)
D. \(4 \frac{1}{4}\)
E. \(8 \frac{1}{2}\)
Kudos for the right answer and explanation
A. \(1 \frac{1}{2}\)
B. \(2 \frac{1}{8}\)
C. \(3\)
D. \(4 \frac{1}{4}\)
E. \(8 \frac{1}{2}\)
Kudos for the right answer and explanation
Re: If 2a + 2b = 7 and 3c + 3d = 15, then the average (arithmeti
[#permalink]
Updated on: 27 Dec 2020, 08:19
Updated on: 27 Dec 2020, 08:19
1
a + b = 7/2
c + d = 5
so
a + b + c + d = 17/2
a + b + c + d /4 = 17 / 8 so B
c + d = 5
so
a + b + c + d = 17/2
a + b + c + d /4 = 17 / 8 so B
Re: If 2a + 2b = 7 and 3c + 3d = 15, then the average (arithmeti
[#permalink]
27 Dec 2020, 03:01
27 Dec 2020, 03:01
1
solve a +b first you get a + b=7/2
then solve c+ d you get c+ d =15/3 which equals c +d=5
now you need find am of a + b + c +d so
AM = (a + b + c + d)/4
which gives you
[7/2 +15/3][/4]
so answer is choice b
average = (sum)/(# of terms) just rember this formula
then solve c+ d you get c+ d =15/3 which equals c +d=5
now you need find am of a + b + c +d so
AM = (a + b + c + d)/4
which gives you
[7/2 +15/3][/4]
so answer is choice b
average = (sum)/(# of terms) just rember this formula
