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If x is different from zero and y=3x
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02 Jan 2021, 02:25
02 Jan 2021, 02:25
Expert Reply
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Question Stats:
86% (00:55) correct
13% (00:25) wrong based on 15 sessions
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If \(x \neq 0\) and \(y=3x\), then \(\frac{x^2+2xy+y^2}{xy} =\)
A. \(1 \frac{1}{3}\)
B. \(2 \frac{4}{9}\)
C. \(3 \frac{1}{9}\)
D. \(3 \frac{1}{3}\)
E. \(5 \frac{1}{3}\)
Kudos for the right answer and explanation
A. \(1 \frac{1}{3}\)
B. \(2 \frac{4}{9}\)
C. \(3 \frac{1}{9}\)
D. \(3 \frac{1}{3}\)
E. \(5 \frac{1}{3}\)
Kudos for the right answer and explanation
Re: If x is different from zero and y=3x
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02 Jan 2021, 08:18
02 Jan 2021, 08:18
1
\(\frac{x^2+2xy+y^2}{xy} =\)
y=3x is given
\(\frac{(x+y)^2}{xy}\)
\(\frac{(x+3x)^2}{x*3x}\)
\(\frac{16x^2}{3x^2}\)
\(\frac{16}{3}\)
\(5 \frac{1}{3}\)
Answer E
y=3x is given
\(\frac{(x+y)^2}{xy}\)
\(\frac{(x+3x)^2}{x*3x}\)
\(\frac{16x^2}{3x^2}\)
\(\frac{16}{3}\)
\(5 \frac{1}{3}\)
Answer E
gmatclubot
Re: If x is different from zero and y=3x [#permalink]
02 Jan 2021, 08:18
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