Carcass wrote:
If a2+2ab+b2=9, then (2a+2b)3=
A. 3
B. 6
C. 9
D. 27
E. 216
Kudos for the right answer and explanation
I'm not crazy about this question. Here's why:
Take:
a2+2ab+b2=9Factor to get:
(a+b)(a+b)=9In other words:
(a+b)2=9So, EITHER
(a+b)=3 OR
(a+b)=−3If
(a+b)=3, then
(2a+2b)3=[2(a+b)]3=[2(3)]3=63=216.
Answer: E
If
(a+b)=−3, then
(2a+2b)3=[2(a+b)]3=[2(−3)]3=(−6)3=−216 Since
−216 is not among the answer choices, the question should read something like: "If
a2+2ab+b2=9, then
(2a+2b)3 COULD equal"
Cheers,
Brent