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a and b are positive
[#permalink]
13 Jan 2021, 06:10
13 Jan 2021, 06:10
Expert Reply
00:00
Question Stats:
82% (00:50) correct
17% (00:45) wrong based on 29 sessions
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a and b are positive
\(b > a\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
\(b > a\)
Quantity A |
Quantity B |
\( \boxed{b^2-a}\) |
\(\boxed{b^2-a^2}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
a and b are positive
[#permalink]
18 Jan 2021, 19:43
18 Jan 2021, 19:43
1
b>a
Let's take b = 2 & a = 1
Qt A
\( \boxed{b^2-a}\)
4 - 1 = 3
Qt B
\(\boxed{b^2-a^2}\)
4 - 1 = 3
\(Qt A = Qt B\)
Now let's take a = 4 & b = 5
we will get Qt A = 21 & Qt B = 9, so \(Qt A > Qt B\)
No definite answer.
Answer D
Let's take b = 2 & a = 1
Qt A
\( \boxed{b^2-a}\)
4 - 1 = 3
Qt B
\(\boxed{b^2-a^2}\)
4 - 1 = 3
\(Qt A = Qt B\)
Now let's take a = 4 & b = 5
we will get Qt A = 21 & Qt B = 9, so \(Qt A > Qt B\)
No definite answer.
Answer D
General Discussion
Re: a and b are positive
[#permalink]
13 Jan 2021, 20:15
13 Jan 2021, 20:15
2
The answer is D
The answer can change between A and B depending on integers or fractions.
Consider b = 8 ; a = 5;
b2-a > b-a
If b = 1/2 a = 1/3
b2-a < b2-a2
Therefore no definitive answer unless more specifics are provided i.e if it is an integer etc
The answer can change between A and B depending on integers or fractions.
Consider b = 8 ; a = 5;
b2-a > b-a
If b = 1/2 a = 1/3
b2-a < b2-a2
Therefore no definitive answer unless more specifics are provided i.e if it is an integer etc
