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The positive difference between the greatest and least value
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28 Dec 2016, 15:12
28 Dec 2016, 15:12
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Question Stats:
47% (01:35) correct
52% (01:40) wrong based on 98 sessions
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\(\frac{6n}{15}, 0.3n, \frac{19n}{50}, \frac{n}{4}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The positive difference between the greatest and least values above |
Three times the positive difference between the two least values above |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Drill 2
Question: 10
Page: 316
Question: 10
Page: 316
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The positive difference between the greatest and least value
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17 Feb 2021, 08:33
17 Feb 2021, 08:33
1
sandy wrote:
\(\frac{6n}{15}, 0.3n, \frac{19n}{50}, \frac{n}{4}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The positive difference between the greatest and least values above |
Three times the positive difference between the two least values above |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Drill 2
Question: 10
Page: 316
Question: 10
Page: 316
Are you missing something? OA must be C if n > 0
\(\frac{6n}{15} = 0.4n, 0.3n, \frac{19n}{50} = 0.38n, \frac{n}{4} = 0.25n\)
Example:
n = 1
Col. A = \(0.4 - 0.25 = 0.15\)
Col. B = \((3)(0.30 - 0.25) = 0.15\)
So, Col. A = Col. B
But, when n = -1
Col. A = \((-0.25) - (-0.4) = 0.15\)
Col. B = \((3)[(-0.38) - (-0.40)] = 0.06\)
So, Col. A > Col. B
Hence, option D
General Discussion
Re: The positive difference between the greatest and least value
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28 Dec 2016, 15:33
28 Dec 2016, 15:33
2
Expert Reply
Explanation
The first thing you need to do is to clean up these expressions. You have 15th, 50th, and decimals, so it is very difficult to compare values.
\(\frac{6n}{15}\) can be reduced to \(\frac{2n}{5}\).
\(0.3n\) is the same as \(\frac{3n}{10}\).
Change your first expression from \(\frac{2n}{5}\) to \(\frac{4n}{10}\).
\(\frac{19n}{50}\) is pretty close to \(\frac{20n}{50}\) or \(\frac{2n}{5}\), the first expression, but a bit smaller.
Because \(\frac{n}{4}\) is clearly the smallest expression and you need only concern yourself with the smallest, the second smallest, and the biggest, you can ignore \(\frac{19n}{50}\).
Convert\(\frac{n}{4}\) to \(\frac{5n}{20}\), and convert your other expressions to 20ths as well.
You now have \(\frac{8n}{15}\), \(\frac{6n}{20}\) and \(\frac{5n}{20}\).
The difference between the smallest and largest is \(\frac{3n}{20}\). Three times the difference between the two smallest is also 3.
The answer is choice C.
The first thing you need to do is to clean up these expressions. You have 15th, 50th, and decimals, so it is very difficult to compare values.
\(\frac{6n}{15}\) can be reduced to \(\frac{2n}{5}\).
\(0.3n\) is the same as \(\frac{3n}{10}\).
Change your first expression from \(\frac{2n}{5}\) to \(\frac{4n}{10}\).
\(\frac{19n}{50}\) is pretty close to \(\frac{20n}{50}\) or \(\frac{2n}{5}\), the first expression, but a bit smaller.
Because \(\frac{n}{4}\) is clearly the smallest expression and you need only concern yourself with the smallest, the second smallest, and the biggest, you can ignore \(\frac{19n}{50}\).
Convert\(\frac{n}{4}\) to \(\frac{5n}{20}\), and convert your other expressions to 20ths as well.
You now have \(\frac{8n}{15}\), \(\frac{6n}{20}\) and \(\frac{5n}{20}\).
The difference between the smallest and largest is \(\frac{3n}{20}\). Three times the difference between the two smallest is also 3.
The answer is choice C.
