At the moment, we're comparing the following:
QUANTITY A: 0.11/d
QUANTITY B: 0.09

Let's test some possible values of d.

If d = 1, then we get:
QUANTITY A: 0.11/d = 0.11/1 = 0.11
QUANTITY B: 0.09
In this case, Quantity A is greater


If d = 0.7 then we get:
QUANTITY A: 0.11/d = 0.11/0.7 ≈ 0.157
QUANTITY B: 0.09
In this case, Quantity A is greater


If d = 0.5, then we get:
QUANTITY A: 0.11/d = 0.11/0.5 = 0.22
QUANTITY B: 0.09
In this case, Quantity A is greater


If d = 0.25, then we get:
QUANTITY A: 0.11/d = 0.11/0.25 = 0.44
QUANTITY B: 0.09
In this case, Quantity A is greater


If d = 0.1, then we get:
QUANTITY A: 0.11/d = 0.11/0.1 = 1.1
QUANTITY B: 0.09
In this case, Quantity A is greater

So, since 0 < d ≤ 1, we can be certain that Quantity A is greater

Righht!! my bad..thanks so much.

I know I did something really wrong here, but I can't figure out why we can't write the equation as this.

While solving this question for the first time, I wrote this.

What is wrong with this approach? Doesn't the equation above explain independent probabilities?

This is more logic than an equation to be frank

C * D = 0.11

To have at least 0.11 C cannot be as low as 0.9. Must be greater

So C > 0.9

A is the answer

Can’t it be possible that
Both probabilities are 0.055
As 0.055*0.055= 0.11
And p(c) is less than 0.09
Another, 0.11
It varies so D ???
Qn isn’t saying min/max so how can we consider p(d)=1 only it could be anything

Posted from my mobile device

Carcass can this question be solved this way?
is this approach right?
probability of both C and D of happening = 0.11
probability of both events not happening is = 0.89
1 - .89*.89 = (Approx 0.2)
QA>QB