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The probability that independent events C and D will both occur is 0.1
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19 Jan 2021, 09:54
19 Jan 2021, 09:54
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Question Stats:
45% (01:02) correct
54% (01:07) wrong based on 108 sessions
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The probability that independent events C and D will both occur is 0.11.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The probability that event C will occur |
0.09 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: The probability that independent events C and D will both occur is 0.1
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19 Jan 2021, 11:37
19 Jan 2021, 11:37
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Carcass wrote:
The probability that independent events C and D will both occur is 0.11.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The probability that event C will occur |
0.09 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Let c = P(event C occurs)
Let d = P(event D occurs)
The probability that independent events C and D will both occur is 0.11
Since events C and D are independent, we can conclude that \(cd = 0.11\)
So if we take this equation and divide both sides by \(d\), we get: \(c=\frac{0.11}{d}\)
So our quantities become:
Quantity A: \(\frac{0.11}{d}\)
Quantity B: 0.09
Since all probabilities can range from 0 to 1, the smallest possible value of \(\frac{0.11}{d}\) occurs when \(d = 1\), in which case \(\frac{0.11}{d}=\frac{0.11}{1}=0.11\)
This means Quantity A must be greater than or equal to 0.11
Answer: A
General Discussion
Re: The probability that independent events C and D will both occur is 0.1
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15 Jul 2021, 08:09
15 Jul 2021, 08:09
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how is smallest possible value is when d=1...shouldn't that be greatest??
and shouldn't ans be "d"?
Please explain.
Let c = P(event C occurs)
Let d = P(event D occurs)
The probability that independent events C and D will both occur is 0.11
Since events C and D are independent, we can conclude that \(cd = 0.11\)
So if we take this equation and divide both sides by \(d\), we get: \(c=\frac{0.11}{d}\)
So our quantities become:
Quantity A: \(\frac{0.11}{d}\)
Quantity B: 0.09
Since all probabilities can range from 0 to 1, the smallest possible value of \(\frac{0.11}{d}\) occurs when \(d = 1\), in which case \(\frac{0.11}{d}=\frac{0.11}{1}=0.11\)
This means Quantity A must be greater than or equal to 0.11
Answer: A
and shouldn't ans be "d"?
Please explain.
GreenlightTestPrep wrote:
Carcass wrote:
The probability that independent events C and D will both occur is 0.11.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The probability that event C will occur |
0.09 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Let c = P(event C occurs)
Let d = P(event D occurs)
The probability that independent events C and D will both occur is 0.11
Since events C and D are independent, we can conclude that \(cd = 0.11\)
So if we take this equation and divide both sides by \(d\), we get: \(c=\frac{0.11}{d}\)
So our quantities become:
Quantity A: \(\frac{0.11}{d}\)
Quantity B: 0.09
Since all probabilities can range from 0 to 1, the smallest possible value of \(\frac{0.11}{d}\) occurs when \(d = 1\), in which case \(\frac{0.11}{d}=\frac{0.11}{1}=0.11\)
This means Quantity A must be greater than or equal to 0.11
Answer: A
