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The value of 12! is closest to:
[#permalink]
20 Jan 2021, 09:32
20 Jan 2021, 09:32
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Question Stats:
50% (02:29) correct
50% (01:57) wrong based on 4 sessions
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The value of \(12!\) is closest to:
A. \((10^6)\)
B. \(3(10^7)\)
C. \(5(10^8)\)
D. \(7(10^9)\)
E. \(9(10^{11})\)
Kudos for the right answer and explanation
A. \((10^6)\)
B. \(3(10^7)\)
C. \(5(10^8)\)
D. \(7(10^9)\)
E. \(9(10^{11})\)
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: The value of 12! is closest to:
[#permalink]
20 Jan 2021, 10:14
20 Jan 2021, 10:14
1
Carcass wrote:
The value of \(12!\) is closest to:
A. \((10^6)\)
B. \(3(10^7)\)
C. \(5(10^8)\)
D. \(7(10^9)\)
E. \(9(10^11)\)
Kudos for the right answer and explanation
A. \((10^6)\)
B. \(3(10^7)\)
C. \(5(10^8)\)
D. \(7(10^9)\)
E. \(9(10^11)\)
Kudos for the right answer and explanation
12! = 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
Let's look for groups of numbers that yield a product that's a power of 10.
NOTE: the answer choices are pretty spread apart, so we can be somewhat aggressive with this strategy.
12! = 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 (11 x 9 = 99, which is very close to 100). So...
≈ 12 x 100 x 10 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 (12 x 8 = 96, which is very close to 100). So...
≈100 x 100 x 10 x 7 x 6 x 5 x 4 x 3 x 2 x 1 (7 x 5 x 3 = 105, which is very close to 100). So...
≈100 x 100 x 10 x 100 x 6 x 4 x 2 x 1 (6 x 4 x 2 x 1 = 48, which is close to 50). So...
≈100 x 100 x 10 x 100 x 50
≈10² x 10² x 10 x 10² x 5 x 10
≈ 5 x 10^8
Answer: C
gmatclubot
Re: The value of 12! is closest to: [#permalink]
20 Jan 2021, 10:14
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