GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A single slice cut from the center of a circular pizza has a
[#permalink]
24 Nov 2020, 11:44
24 Nov 2020, 11:44
Expert Reply
3
Bookmarks
00:00
Question Stats:
44% (02:43) correct
55% (03:14) wrong based on 36 sessions
Hide Show timer Statistics
A single slice cut from the center of a circular pizza has an edge length (from the center of the pizza to the edge of the crust) of 5″, has an arc length of 1.25π″, and weighs 4 ounces. If a serving weighs 8 ounces, then, to the nearest integer, what is the largest number of servings that six 6″ diameter pizzas can yield? (Note that servings must weigh 8 ounces, but they do not need to be equal in shape.)
A. 1
B. 4
C. 6
D. 8
E. 9
A. 1
B. 4
C. 6
D. 8
E. 9
Re: A single slice cut from the center of a circular pizza has a
[#permalink]
25 Nov 2020, 00:17
25 Nov 2020, 00:17
1
Sample pizza r=5; d=10; c=10π; thus a single serving is 1/4th of this (c/1.25π=1/2 serving; 1/4*c=1 serving)
area of single serving=(r^2π)/4=25π/4=6.25π
Area of the six 6 inch diameter pizzas=6/2=r=3; 3^2π*6=54π; 54π/6.25π=8.64
Thus, it can serve 8 full servings. It could be argued that this, rounded to the nearest number is 9, which I regard as kinda unfair because that seems a very reasonable interpretation, but that's the value of reading the question, and it's somewhat reinforced by saying that servings "must weight" 8 ounces.
Ways to get tripped up:
-Not recognize that the reference pizza and the "new" pizzas are different
-Not recognize that the "new" pizzas have a diameter of 6, not a radius, as was given in the reference
-Miss the point about what constitutes a serving
area of single serving=(r^2π)/4=25π/4=6.25π
Area of the six 6 inch diameter pizzas=6/2=r=3; 3^2π*6=54π; 54π/6.25π=8.64
Thus, it can serve 8 full servings. It could be argued that this, rounded to the nearest number is 9, which I regard as kinda unfair because that seems a very reasonable interpretation, but that's the value of reading the question, and it's somewhat reinforced by saying that servings "must weight" 8 ounces.
Ways to get tripped up:
-Not recognize that the reference pizza and the "new" pizzas are different
-Not recognize that the "new" pizzas have a diameter of 6, not a radius, as was given in the reference
-Miss the point about what constitutes a serving
A single slice cut from the center of a circular pizza has a
[#permalink]
21 Jan 2021, 06:55
21 Jan 2021, 06:55
1
DFXR
Hi
I am not able to get the idea behind this
Area of the six 6 inch diameter pizzas=6/2=r=3; 3^2π*6=54π; 54π/6.25π=8.64
D = 6, r= 3, so area must be Pi r*r. so Pi*3*3 = 9 pi . why is it again multiplied by 6 and is 54pi?
pls help.
Hi
I am not able to get the idea behind this
Area of the six 6 inch diameter pizzas=6/2=r=3; 3^2π*6=54π; 54π/6.25π=8.64
D = 6, r= 3, so area must be Pi r*r. so Pi*3*3 = 9 pi . why is it again multiplied by 6 and is 54pi?
pls help.
