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Lines AB and CD are parallel. What is x?
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01 Dec 2020, 03:09
01 Dec 2020, 03:09
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Question Stats:
100% (00:35) correct
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GRE the value of x.jpg [ 10.45 KiB | Viewed 1939 times ]
Lines AB and CD are parallel. What is x?
A. 100°
B. 110°
C. 105°
D. 120°
E. 130°
Kudos for the right answer and explanation
Re: Lines AB and CD are parallel. What is x?
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31 Dec 2020, 19:20
31 Dec 2020, 19:20
1
Let's take the intersection as point E
Now both lines are parallel,
On line CD let's take the first point is P and second as Q. So C - P - Q - D
EQD = 140 so EQP = 40 As the sum for both the angle should be 180.
ABP = 30 :- AB & CD are parallel lines so BPQ will be 30 as well.
Now in triangle EPQ the sum of internal angles should be 180.
So x + 30 + 40 = 180
x = 110
Answer B
Now both lines are parallel,
On line CD let's take the first point is P and second as Q. So C - P - Q - D
EQD = 140 so EQP = 40 As the sum for both the angle should be 180.
ABP = 30 :- AB & CD are parallel lines so BPQ will be 30 as well.
Now in triangle EPQ the sum of internal angles should be 180.
So x + 30 + 40 = 180
x = 110
Answer B
Lines AB and CD are parallel. What is x?
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26 Jan 2021, 07:41
26 Jan 2021, 07:41
1
From question,
Line AB and CD are parallel.
Let us consider the point for angle x as O.
Let us consider the point for angle 140 degree as P.
Hence angle OCP = 30 degree (It is alternate to angle B)
Now angle OPC = 40 degree (OPC + 140 = 180 degree, angle in straight line = 180 degree)
Therefore, angle x = 110( sum of angle inside a triangle = 180 degree)
Line AB and CD are parallel.
Let us consider the point for angle x as O.
Let us consider the point for angle 140 degree as P.
Hence angle OCP = 30 degree (It is alternate to angle B)
Now angle OPC = 40 degree (OPC + 140 = 180 degree, angle in straight line = 180 degree)
Therefore, angle x = 110( sum of angle inside a triangle = 180 degree)
Attachments
parallel_label.png [ 8.96 KiB | Viewed 1726 times ]
