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A lawn covers 108.6 square feet. Russ mowed all of the lawn in three
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01 Feb 2021, 07:36
01 Feb 2021, 07:36
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92% (01:28) correct
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A lawn covers 108.6 square feet. Russ mowed all of the lawn in three evenings. He mowed \(\frac{2}{9}\) of the lawn during the first evening. He mowed twice that amount on the second evening. On the third and final evening he mowed the remaining lawn. How many square feet were mowed the third evening?
Kudos for the right answer and explanation
Show: :: OA
36.2
Kudos for the right answer and explanation
Re: A lawn covers 108.6 square feet. Russ mowed all of the lawn in three
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01 Feb 2021, 07:44
01 Feb 2021, 07:44
1
Total 108.6 sq ft Lawn
Day 1
\(\frac{2}{9}\) of total = \(\frac{2}{9}\)*108.6 = 24.13 sq ft
remaining after day 1 = \(108.6 - 24.13\) = 84.466
Day 2
twice the lawn mowed on day 1
hence 48.26 sq ft
remaining after day 2 = \(84.466 - 48.26\) = 36.206
Lawn mowed on Day 3 = 36.21 sq ft
Day 1
\(\frac{2}{9}\) of total = \(\frac{2}{9}\)*108.6 = 24.13 sq ft
remaining after day 1 = \(108.6 - 24.13\) = 84.466
Day 2
twice the lawn mowed on day 1
hence 48.26 sq ft
remaining after day 2 = \(84.466 - 48.26\) = 36.206
Lawn mowed on Day 3 = 36.21 sq ft
Re: A lawn covers 108.6 square feet. Russ mowed all of the lawn in three
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23 Oct 2024, 01:20
23 Oct 2024, 01:20
1
day1: 2/9
day2: 4/9
day3: 1-(6/9)=3/9=1/3
108.6/3= 36.2 sq
day2: 4/9
day3: 1-(6/9)=3/9=1/3
108.6/3= 36.2 sq
